# ch3oh + co

CH3OH + COCH3COOH

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### Word Equation

Methanol + Carbon Monoxide = Acetic Acid

One mole of

Methanol [CH3OH]

and one mole of

Carbon Monoxide [CO]

combine lớn sườn one mole of

Acetic Acid [CH3COOH]

• ### Methanol - CH3OH

Methyl Hydroxide Hydroxymethane Monohydroxymethane Colonial Spirit Columbian Spirit Spirit Of Wood Pyroxylic Spirit Methylol CH3OH Molar Mass CH3OH Oxidation Number

### Thermodynamics

Thermodynamics of the reaction can be calculated using a lookup table.

#### Is the Reaction Exothermic or Endothermic?

CH3OH (g methanol) CO (g) CH3COOH (l acetic acid) 1 mol -201.08304 kJ/mol 201.08304 kJ 1 mol -110.54128 kJ/mol 110.54128 kJ 1 mol -484.13064 kJ/mol -484.13064 kJ -311.62432 kJ -484.13064 kJ -172.50632 kJ

ΣΔH°f(reactants) > ΣΔH°f(products), sánh CH3OH + CO = CH3COOH is exothermic (releases heat).

#### Is the Reaction Exoentropic or Endoentropic?

ΔS = Sproducts - Sreactants. If ΔS < 0, it is exoentropic. If ΔS > 0, it is endoentropic.

CH3OH (g methanol) CO (g) CH3COOH (l acetic acid) 1 mol 239.70136 J/(mol K) -239.70136 J/K 1 mol 197.9032 J/(mol K) -197.9032 J/K 1 mol 159.8288 J/(mol K) 159.8288 J/K 437.60456 J/K 159.8288 J/K -277.77576 J/K

ΣΔS°(reactants) > ΣΔS°(products), sánh CH3OH + CO = CH3COOH is exoentropic (decrease in entropy).

#### Is the Reaction Exergonic or Endergonic?

ΔG = Gproducts - Greactants. If ΔG < 0, it is exergonic. If ΔG > 0, it is endergonic.

CH3OH (g methanol) CO (g) CH3COOH (l acetic acid) 1 mol -162.42288 kJ/mol 162.42288 kJ 1 mol -137.27704 kJ/mol 137.27704 kJ 1 mol -389.9488 kJ/mol -389.9488 kJ -299.69992 kJ -389.9488 kJ -90.24888 kJ

ΣΔG°(reactants) > ΣΔG°(products), sánh CH3OH + CO = CH3COOH is exergonic (releases energy).

### Reaction Expressions

Kc or Q = ( [CH3COOH] ) / ( [CH3OH] [CO] )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -(Δ[CH3OH] / Δt) = -(Δ[CO] / Δt) = (Δ[CH3COOH] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)

## Instructions

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds lớn avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

## How To Balance Equations

Read our article on how lớn balance chemical equations or ask for help in our chat.

You can also ask for help in our chat or forums.

## Balance CH3OH + CO = CH3COOH Using the Algebraic Method

To balance the equation CH3OH + CO = CH3COOH using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

1. ### Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable lớn represent the unknown coefficients.

a CH3OH + b CO = c CH3COOH

2. ### Create a System of Equations

Create an equation for each element (C, H, O) where each term represents the number of atoms of the element in each reactant or product.

C: 1a + 1b = 2c H: 4a + 0b = 4c O: 1a + 1b = 2c

3. ### Solve For All Variables

Use substitution, Gaussian elimination, or a calculator lớn solve for each variable.

• 1a + 1b - 2c = 0
• 4a - 4c = 0
• 1a + 1b - 2c = 0

Use your graphing calculator's rref() function (or an online rref calculator) lớn convert the following matrix into reduced row-echelon-form:

[ 1 1 -2 0] [ 4 0 -4 0] [ 1 1 -2 0]

The resulting matrix can be used lớn determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result lớn get the lowest, whole integer values.

• a = 1 (CH3OH)
• b = 1 (CO)
• c = 1 (CH3COOH)
4. ### Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

CH3OH + CO = CH3COOH

Reactants Products C 2 2 ✔️ 4 4 ✔️ 2 2 ✔️

Since there is an equal number of each element in the reactants and products of CH3OH + CO = CH3COOH, the equation is balanced.

## Balance CH3OH + CO = CH3COOH Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in CH3OH + CO = CH3COOH must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used lớn balance one element at a time until both sides are equal and the chemical equation is balanced.

### 1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
CH3OHCOTotalCH3COOHTotal
C11222✔️
H4444✔️
O11222✔️

The number of atoms of each element on both sides of CH3OH + CO = CH3COOH is equal which means that the equation is already balanced and no additional work is needed.

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